Date: 2015nov17 Update: 2025oct8 Language: Java Keywords: overlap, collision, union, ontop, inside Q. Java: Test if 2 rectangles intersect A. The Java class java.awt.Rectangle has a method for this. So if are using it you can just call intersects() but not you can adapt the code as shown in a full example:

import java.awt.Rectangle; class Demo { public static boolean intersects(final Rectangle a, final Rectangle b) { final int neww = (a.x + a.width < b.x + b.width ? a.x + a.width : b.x + b.width) - (a.x < b.x ? b.x : a.x); final int newh = (a.y + a.height < b.y + b.height ? a.y + a.height : b.y + b.height) - (a.y < b.y ? b.y : a.y); return (neww > 0 && newh > 0); } public static final void main(String []args) { { // Test 1 final int x = 10, y = 10, width = 100, height = 100; Rectangle r1 = new Rectangle(x, y, width, height); Rectangle r2 = new Rectangle(x + 5, y + 5, width, height); boolean result = intersects(r1, r2); System.out.println("intersects=" + result + " (true is expected)"); } { // Test 2 final int x = 10, y = 10, width = 10, height = 10; Rectangle r1 = new Rectangle(x, y, width, height); Rectangle r2 = new Rectangle(x + 20, y + 20, width, height); boolean result = intersects(r1, r2); System.out.println("intersects=" + result + " (false is expected)"); } } }

Output:

intersects=true (true is expected) intersects=false (false is expected)